I kept working on String 2, and I realised that I will most likely finish String 2 before the quarter ends. This is because there aren't as many string problems as array problems. Of course, I could be wrong in saying that, because they might turn out to be very hard. But if I keep working at the pace that I am now, I should finish all the problems before the year ends.
I am still getting used to strings again. I was working on a problem for the whole class, and it was only at the end of class when I told Mr. Daly that I was very confused about all of these problems, that he explained to me a very important concept in Strings. Less of a concept, more of a method in coding. The indexOf method. indexOf tells you when a word starts in the string. For example, if my string is "hellomynameis" and I code str.indexOf("my"); the computer will tell me at what part of the string the word my comes in. So in that case, I would get the number 4.
This method will come in handy a lot in my String 2 problems, because they often ask me to do things that require taking a part of a string and doing something with it. Up until now, I was confused how to. But from now on, I'm sure that this method will help me.
However, I won't be showing an indexOf problem today. I will be showing one for next class's blog.
Here is today's problem:
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| Return true if the given string contains a "bob" string, but where the middle 'o' char can be any char. bobThere("abcbob") → true bobThere("b9b") → true bobThere("bac") → false |
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